How to Calculate Work Required to Stop a Rolling Hoop?

What is the amount of work needed to stop a 150 kg hoop rolling along a horizontal floor with a speed of 0.130 m/s? The work needed to stop the hoop is equal to the kinetic energy (KE) of the hoop. The formula for calculating KE is KE = 0.5 * mass * velocity^2. In this case, the mass of the hoop is 150 kg and the velocity is 0.130 m/s. Substituting these values into the formula, we get:

KE = 0.5 * 150 kg * (0.130 m/s)^2

KE = 0.5 * 150 * 0.0169

KE = 1.3495 J

Therefore, the amount of work that must be done on the hoop to stop it is 1.3495 Joules.

It is important to note that the work needed to stop the hoop is equal to the kinetic energy it possesses due to its motion. This energy must be dissipated in some form, such as through friction or another means of stopping the hoop's movement.

← Importance of proper volt range selection when using a vom Density of air in a hot air balloon lift a 50 kg person and max weight with helium →

More Posts: