How to Make 0.222 M Nitric Acid Solution?

What is the required concentration of nitric acid to make 225 mL of 0.222 M solution?

How much concentrated nitric acid is required to achieve the desired solution?

Answer:

To make a 0.222 M solution of nitric acid with a volume of 225 mL, you will need 3.12 mL of 16 M nitric acid.

When preparing a solution of a specific concentration, it is important to calculate the amount of concentrated solution needed to achieve the desired concentration. In this scenario, the task is to make a 0.222 M solution of nitric acid with a total volume of 225 mL.

The formula used to calculate the volume of concentrated nitric acid required is:

V2 = (M1 * V1) / M2

Where:

• V2 is the volume of concentrated nitric acid needed
• M1 is the desired concentration of nitric acid (0.222 M)
• V1 is the total volume of the solution (225 mL)
• M2 is the concentration of the concentrated nitric acid (16 M)

By substituting the values into the formula, we get:

V2 = (0.222 M * 225 mL) / 16 M = 3.12 mL

Therefore, you will need 3.12 mL of 16 M nitric acid to prepare 225 mL of 0.222 M nitric acid solution. Make sure to measure accurately to achieve the desired concentration.