# The Physics of Acceleration in F-18 Fighter Jet Takeoff

## Acceleration Calculation for F-18 Fighter Jet Takeoff

In order for an F-18 fighter jet to take off from an aircraft carrier, it needs to reach a speed of 75 m/s by quickly accelerating down a 90 m long runway. If the F-18 starts from rest, what acceleration does the fighter jet undergo during takeoff?

### Question:

What is the acceleration of the F-18 fighter jet during takeoff?

### Final Answer:

**The acceleration of the F-18 fighter jet during takeoff is 1.25 m/s^2.**

**Explanation:** To determine the acceleration, we can use the kinematic equation \(v^2 = u^2 + 2as\), where v is the final velocity, u is the initial velocity (which is 0 m/s as the jet starts from rest), a is the acceleration, and s is the displacement.

Rearranging the equation to solve for acceleration, we get \(a = \frac{v^2 - u^2}{2s}\). Plugging in the given values, we find the acceleration.

The positive acceleration indicates that the fighter jet is undergoing a uniform acceleration along the runway, gradually reaching the required takeoff speed.

## Physics of F-18 Fighter Jet Takeoff

The takeoff of aircraft from carriers involves complex physics principles and calculations. The acceleration plays a crucial role in ensuring the aircraft reaches the required speed for a successful takeoff.

### Question:

What acceleration does the F-18 fighter jet undergo during takeoff from an aircraft carrier?

### Final Answer:

**The F-18 fighter jet undergoes an acceleration of approximately 31.25 m/s^2 in order to reach a speed of 75 m/s when taking off from a 90 m long runway of an aircraft carrier.**

**Explanation:** To determine the acceleration that an F-18 fighter jet undergoes during takeoff from an aircraft carrier, we can use the kinematic equation: \(v^2 = u^2 + 2as\), where v is the final velocity (75 m/s), u is the initial velocity (0 m/s as the jet starts from rest), a is the acceleration, and s is the displacement (90 m, the length of the runway).

By substituting the known values into the equation, we find that the acceleration is approximately 31.25 m/s^2.