Stunt Car Cliff Jump Calculation
How long will the car be in freefall?
A. Approximately 3.9 seconds
How far from the base of the cliff will the car land?
B. Approximately 59.6 meters
What is the stunt car's final velocity?
C. Approximately 41.22 m/s
1) The time duration of the car in free fall is approximately 3.9 seconds
2) The distance from the base of the cliff the stunt car will land is approximately 59.6 meters
3) The speed of the stunt car when it lands is approximately 41.22 m/s
When calculating the stunt car cliff jump scenario, we first need to determine the time the car will be in freefall. This can be done using the equation for free fall from a height, h. By substituting the known values of h = 74.7 m and g = 9.81 m/s², we find that the car will be in freefall for approximately 3.9 seconds.
Next, we calculate the distance from the base of the cliff the stunt car will land. This can be found by multiplying the horizontal speed of the car (15.28 m/s) by the time in freefall (3.9 seconds), resulting in a distance of approximately 59.6 meters.
Finally, we determine the stunt car's final velocity when it lands. By applying the equations for vertical velocity and resultant speed, we find that the speed of the stunt car when it lands is approximately 41.22 m/s.