How Much Work is Required to Stop a Rolling Hoop?

Calculating Work Done on the Hoop

When a 150 kg hoop rolls along a horizontal floor with a center of mass speed of 0.220 m/s, the work done on the hoop to stop it is -3.66 J.

The work done on the hoop is equal to the change in kinetic energy of the hoop, which can be calculated using the formula: Work done = ∆KE = 1/2 mv².

Given the initial velocity (v) of the hoop, we can determine the kinetic energy of the hoop while it's in motion.

Using the formula for kinetic energy: Kinetic energy = 1/2mv², where m = mass of the hoop and v = velocity of the hoop, substitute the values into the equation:

Kinetic energy = 1/2 × 150 kg × (0.220 m/s)² = 3.66 J

As the hoop comes to a stop, the final velocity of the hoop is 0, and the work done on the hoop can be calculated as: Work done = ∆KE = KE final - KE initial.

Therefore, the work done on the hoop to stop it is -3.66 J.

The answer to the question of how much work is required to stop a rolling hoop is -3.66 J.