How much Greater is the Internal Energy of Helium in a Ball?

What is the difference in internal energy of helium in a helium-filled rigid ball with a gauge pressure of 0.200 atm and a volume of 10.0 L compared to when it is at zero gauge pressure? The internal energy of the helium in the ball is 0.200 times greater than it would be at zero gauge pressure.

Internal Energy of Helium in a Ball

Internal Energy Calculation: The internal energy of a gas is given by the equation U = nKT, where U is the internal energy, n is the number of moles of gas, K is the Boltzmann constant, and T is the temperature.

Comparison of Internal Energies

Direct Proportion: The internal energy is directly proportional to the pressure of the gas. In this case, when the helium-filled rigid ball has a gauge pressure of 0.200 atm, the internal energy is 0.200 times greater than it would be at zero gauge pressure.

Final Answer

The internal energy of the helium in the ball is 0.200 times greater than it would be at zero gauge pressure.

← Analyze this rlc circuit with resistance r 21 OE and inductance l 170 mh Escape speed understanding the minimum speed required to break free from gravitational pull →