What is the amount of energy needed to raise a 97 kg barbell by 1.25 meters?
The energy required to lift a 97 kg barbell by 1.25 meters can be calculated using the formula: PE = mgh, where PE represents potential energy, m is the mass of the object (97 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height the object is raised (1.25 meters). By substituting the values into the formula, we get:
PE = (97 kg)(9.8 m/s^2)(1.25 meters) = 1,188.25 J
Therefore, the energy required to lift a 97 kg barbell by 1.25 meters is 1,188.25 Joules.
Calculation of Potential Energy
Potential Energy (PE) = mass x acceleration due to gravity x height
In this case, the mass of the barbell is 97 kg, the acceleration due to gravity is 9.8 m/s^2, and the height it is raised is 1.25 meters. Plugging these values into the formula, we get:
PE = (97 kg) x (9.8 m/s^2) x (1.25 meters) = 1,188.25 Joules
So, the potential energy required to lift a 97 kg barbell by 1.25 meters is 1,188.25 Joules. This energy is needed to overcome the gravitational force acting on the barbell and raise it to the specified height.
Potential energy is a form of energy that depends on the position of an object relative to its surroundings. In this case, as the barbell is lifted against the force of gravity, it gains potential energy that can be converted into kinetic energy when it is released and falls back down. Understanding the amount of energy required for such tasks can help in various fields such as physics, engineering, and sports training.