Calculating Acceleration and Final Velocity of a Body
What is the question involving the acceleration and final velocity of a body?
A body starting from rest and executing an accelerated motion covers a distance of 9m in 6 seconds.
Calculate:
i. The acceleration
ii. The final velocity
Answer:
The acceleration of the body is 0.5 m/s^2, calculated using the kinematic equation for distance. The final velocity is found to be 3.0 m/s using the equation for velocity which incorporates the found acceleration.
The question involves calculating the acceleration and final velocity of a body starting from rest and covering a distance of 9m in 6 seconds under accelerated motion. To find the acceleration (a), we use the kinematic equation s = ut + (1/2)at^2, where s is the distance covered, u is the initial velocity (0 m/s since the body starts from rest), t is the time, and a is the acceleration.
Solving for acceleration, we get:
a = 2s/t^2
a = 2 * 9 m / (6 s)^2
a = 18 m / 36 s^2
a = 0.5 m/s^2
To find the final velocity (v), we use the equation v = u + at.
v = 0 m/s + (0.5 m/s^2 * 6 s)
v = 3.0 m/s
Hence, the acceleration is 0.5 m/s^2 and the final velocity is 3.0 m/s.