Introduction to MIPS Assembly Language

What is put in register $8 after lb $8,0($5) is executed?

a. 0x11111180

b. 0x80000000

c. 0x00000080

d. 0xF

Final answer:

The MIPS assembly language instruction 'lb $8,0($5)' will put the value 0x00000080 into register $8 based on the provided initial conditions.

Explanation: In MIPS assembly language, the lb instruction stands for load byte. The command lb $8,0($5) will load the byte at the memory address contained in register $5 into register $8. Given the initial conditions where memory at 0x10000000 contains 0x80 and register $5 contains 0x10000000, the value stored at the memory address in register $5 will be put into register $8. Therefore, after the execution of the instruction, the value that would be put into register $8 would be 0x00000080 (option c).

This operation is known as a 'load byte' operation.