What is the enthalpy of combustion when 1 mol C6H6(g) completely reacts with oxygen? The enthalpy of combustion of 1 mole of benzene is 3169 kJ/mol. The first step in answering this question is to obtain the balanced thermochemical equation of the reaction. The thermochemical equation shows the amount of heat lost or gained. The thermochemical equation for the combustion of benzene is: 2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔrH° = -3169 kJ/mol We can see that 1 mole of benzene releases about 3169 kJ/mol of heat.

Question

What is the enthalpy of combustion when 1 mol C6H6(g) completely reacts with oxygen?     The enthalpy of combustion of 1 mole of benzene is 3169 kJ/mol.     The first step in answering this question is to obtain the balanced thermochemical equation of the reaction. The thermochemical equation shows the amount of heat lost or gained.     The thermochemical equation for the combustion of benzene is:     2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔrH° = -3169 kJ/mol     We can see that 1 mole of benzene releases about 3169 kJ/mol of heat.

Hilbert · Answer

Answer:     -3169 kJ/mol     Explanation:     The enthalpy of combustion of 1 mole of benzene is -3169 kJ/mol. This means that when 1 mole of C6H6(g) completely reacts with oxygen, it releases 3169 kJ of heat energy. The negative sign indicates that the reaction is exothermic, meaning it releases heat to the surroundings.     Enthalpy of combustion is a measure of the energy released when a substance undergoes complete combustion with oxygen. In the case of benzene, the combustion reaction results in the formation of carbon dioxide and water, along with the release of energy in the form of heat.     This information is crucial in understanding the energy changes associated with chemical reactions and can be used in various thermodynamic calculations and analyses.

The Enthalpy of Combustion of Benzene

What is the enthalpy of combustion when 1 mol C6H6(g) completely reacts with oxygen?

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