How to Calculate the Volume of 6.00 M NaOH Needed to Prepare 338 ml of 0.155 M NaOH

Understanding the Problem

To prepare 338 ml of 0.155 M NaOH, you need to calculate how many ml of 6.00 M NaOH are required.

Solution

Step 1: The molarity formula can be used here. The equation is M1 V1 = M2 V2, where M1 is the molarity of the first solution, V1 is the volume of the first solution in liters, M2 is the molarity of the second solution, and V2 is the volume of the second solution in liters.

Step 2: Calculate the volume of the first solution (V1) by using the formula. Substitute the given values into the equation: 338 ml × 0.155 M = V1 × 6.00 M. Solve for V1: V1 = (338 × 0.155) / 6.00 ml = 8.73 ml.

Step 3: In order to obtain a final volume of 338 ml with a concentration of 0.155 M, you need to mix 8.73 ml of 6.00 M NaOH with 329.27 ml of water. Therefore, the amount of 6.00 M NaOH required to prepare 338 ml of 0.155 M NaOH is 8.73 ml.

How many ml of 6.00 M NaOH are needed to prepare 338 ml of 0.155 M NaOH?

To prepare 338 ml of 0.155 M NaOH, 8.73 ml of 6.00 M NaOH is required.