How many moles of CO2 are produced from 15.6 g of NaHCO3?

Calculation of the moles of CO2 produced from NaHCO3

When 15.6 g of NaHCO3 is reacted, the amount of CO2 produced can be calculated using stoichiometry.

The molar mass of NaHCO3 is approximately 84 g/mol.

First, we need to calculate the number of moles of NaHCO3 in 15.6 g:

Number of moles = Mass / Molar mass

Number of moles = 15.6 g / 84 g/mol = 0.185 moles

1 mole of bicarbonate (NaHCO3) produces 1 mole of CO2 according to the balanced chemical equation.

Therefore, 0.185 moles of NaHCO3 will produce 0.185 moles of CO2.

Answer:

0.357 moles

Explanation:

Using the same calculation as before, by dividing the mass by the molar mass of NaHCO3 (84 g/mol), we get 0.357 moles of CO2 produced.