Electric Field Calculation for Moving Electron

What is the direction of the electric field in this scenario? How can we calculate the distance the electron travels before coming to rest and the time it takes for the electron to come to rest?

The direction of the electric field is opposite to the initial velocity of the electron, which means it is in the negative x direction. To calculate the distance the electron travels before coming to rest, we can use the equation d = -V02 / (2a). And to find the time it takes for the electron to come to rest, we can use the equation t = -V0 / a.

Explanation:

(a) The direction of the electric field is opposite to the initial velocity of the electron. Since the electron has an initial velocity in the positive x direction, the electric field must be in the negative x direction.

(b) To find the distance the electron travels before coming to rest, we can use the equation: V2 = V02 + 2ad where V is the final velocity (which is 0), V0 is the initial velocity, a is the acceleration, and d is the distance. Rearranging the equation, we get: d = -V02 / (2a). Substituting the given values, we have: d = - (5.00 x 106)2 / (2 x 2.00 x 105).

(c) To find the time it takes for the electron to come to rest, we can use the equation: V = V0 + at where V is the final velocity (which is 0), V0 is the initial velocity, a is the acceleration, and t is the time. Rearranging the equation, we get: t = -V0 / a. Substituting the given values, we have: t = - (5.00 x 106) / 2.00 x 105.

(d) When the electron returns to its starting point, it will have the same velocity as its initial velocity. Therefore, the velocity when it returns to its starting point is 5.00 x 106 m/s.

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