Determining the Concentration of NaOH Using Titration Data

What is the concentration of the NaOH?

A. 0.16 M
B. 0.22 M
C. 4.5 M
D. 6.3 M

Answer: 0.16 M

Explanation: We are given the following data:

We have the volume of NaOH as 34.8 mL, the volume of HCl as 29.6 mL, and the molarity of HCl as 0.19 M. To determine the concentration of NaOH, we will follow these steps:

  1. Write the reaction equation: NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)
  2. Determine the moles of HCl: Moles = Molarity × Volume = 0.19 M × 0.0296 L = 0.005624 moles
  3. Since 1 mole of NaOH reacts with 1 mole of HCl, moles of NaOH equal moles of HCl, which is 0.005624 moles
  4. Calculate the concentration of NaOH: Concentration/Molarity = Number of moles ÷ Volume = 0.005624 moles ÷ 0.0348 L = 0.1616 M = 0.16 M

Therefore, the concentration of NaOH is 0.16 M based on the titration data provided. Cheers to accurate chemistry calculations!

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