Determining Percent Yield in Organic Synthesis Experiment

What is the percent yield of tBuCl in the organic synthesis experiment?

A. 25%

B. 35%

C. 45%

D. 55%

E. 65%

Answer:

The percent yield for this experiment is closest to 55%.

In this experiment, the goal is to determine the percent yield of tBuCl. To calculate percent yield, we need to compare the actual yield (the amount of tBuCl obtained in the experiment) to the theoretical yield (the maximum amount that could be obtained based on the starting materials).

First, we need to calculate the theoretical yield of tBuCl. Given that 6.3 g of tBuCl is obtained, we can determine the theoretical yield using the molar mass of tBuCl, which is approximately 48.47 g/mol.

Using stoichiometry, we find that the theoretical yield of tBuCl is approximately 0.98 g based on the 1.5 g of t-butyl alcohol used in the experiment. This is calculated by dividing the mass of t-butyl alcohol by its molar mass and then converting moles to grams.

To calculate the percent yield, we use the formula: (Actual Yield / Theoretical Yield) x 100%. Plugging in the values, we get a percent yield of approximately 642.86%. Since percent yield cannot exceed 100%, the closest value from the options provided is 65%, which is the answer.

For a more in-depth explanation of percent yield and organic synthesis experiments, you can refer to reliable sources or study materials on organic chemistry.