Calculating the Amount of Sugar in a Sugar Water Solution

How many grams of sugar are there in a 6.3 Kg sugar water solution with a 3.8% mass percentage?

Calculation of Sugar Amount in Solution

The amount of sugar in the solution is 239.4 grams. In this case, sugar is the solute, and water is the solvent. Sugar is the solute that is dissolved in an aqueous solution with a mass of 6.3 kilograms.

One kilogram is equal to 1,000 grams. Therefore, 1 kilogram (kg) = 1,000 grams (g).

The amount of sugar can be calculated using the simple rule of three:

6,300 g ________ 100 %

X ______________ 3.8 %

X = (3.8 x 6,300) / 100 = 239.4 grams

Understanding the Calculation

By utilizing the percentage of sugar in the solution, which is 3.8%, and the total mass of the solution, which is 6.3 kilograms, we can determine the amount of sugar present in the solution. The rule of three is a simple mathematical method that allows us to find an unknown value based on three known values. In this case, we know the total mass of the solution, the percentage of sugar, and we are looking for the amount of sugar in grams.

First, we convert the total mass of the solution from kilograms to grams by multiplying 6.3 kg by 1,000 as there are 1,000 grams in 1 kilogram. This gives us 6,300 grams as the total mass of the solution.

Next, we set up the rule of three equation where 6,300 grams represents 100% of the solution. We then calculate what percentage of 6,300 grams corresponds to 3.8% using cross-multiplication, which results in 239.4 grams of sugar in the solution.

Therefore, the 6.3 kg sugar water solution contains 239.4 grams of sugar.

← Tips for choosing the right ether for your experiment Nitric acid understanding its classification →